Randell Mills GUT - Who can do the calculations?

I'll let you know what Dr. Mills says. Or you can just join us at The Society For Classical Physics. Sorry if I came off as a jerk, you seem to be obviously willing to take an honest look at the theory.

Furthermore, not all parts of the theory are fully fleshed out as you can see, but what it does predict it does so with extreme accuracy and within the confines of classical physics and fundamental constants. There is room to make original contributions to the theory.

I suggested the design of using liquid electrodes last year on the forum to isolate the energetic transition reactions from the solid parts of the reactor and prevent them from melting or vaporizing. This was prior to revealing any liquid fuel injection or liquid electrodes being used in the latest design revealed last week.

From a Mills theory point of view, can anybody who knows Mills theory understand how the plasma can self sustained for many minutes on end just with the liquid metal electrodes going.

The vaporized silver provides the conductive matrix, the heat provides the kinetic energy to the reactants which are catalyst and atomic hydrogen.

The kinetic energy is what is responsible for initiating the transition reactions (specifically dipole/multipole resonant collisions destabilizing the orbitsphere causing radial acceleration and release of electric potential between electron and proton). If the plasma wasn't contained within the pressure vessel the conditions conducive to the reactions would not persist. The current is mainly to alleviate charge buildup and to provide the initial kinetic energy to the reactants.

The energy obviously comes from the transition reactions which are releasing ~100 or more eVs per event depending on which fractional state is being catalyzed. There could likely even be disproportionation occurring which is when hydrinos collide and drop to even lower energy levels. This also likely occurs within the corona of our star.

If the plasma wasn't confined somehow, it would simply dissipate.

Even in single shot open air tests three years ago the plasma persisted much longer after current ceased to flow which current theory cannot explain. In all cases there is no high field, only a maximum of 5 volts.

Why not just go on the forum and ask Dr. Mills directly?

If the magic is in the kinetic energy and not in the driving electric current, then the hydrino reaction can spread over N numbers of silver fountains...say 100 electrode sets...an electrode array where the reaction in one electrode set can activate the reaction in many other electrode sets that are nearby the prime driver set.

There's no magic, it's classical physics not QM.

Quote from B Yoshikazu

There's no magic, it's classical physics not QM.

If you say: "the plasma persisted much longer after current ceased to flow which current theory cannot explain" then how can you be so sure of what you assum?

I meant according to the current mainstream physics paradigm, it is explained using classical physics (GUTCP) as I have described above.

I don't claim to be the world's authority on GUTCP but I think I got the major points mostly right. Again, Dr. Mills doesn't mind answering questions on his Society for Classical Physics forum. We interact with him on a daily basis pretty much.

Also I wasn't sure if you were being sarcastic with your prior posts, but look at what happens in the corona of the Sun. If GUTCP is right, disproportionation hydrino reactions occur on a massive scale providing the high energy photons to produce the ionized species of elements observed in the spectrum, not millions of degrees temperature as is currently assumed.

In regards to Epimetheus's post above, I can't remember where I read it, it was either on the forum or in Brett's book, but apparently many years ago, Hermann Haus told Dr. Mills privately that he had correctly solved for the structure of the electron classically. At the time he did not wish to make "waves" so to speak through public acknowledgement.

In regards to K-Capture Eric seems to be asking specifically about the case of capture of the inner shell; I've posted a question on the other forum so we'll see what Dr. Mills says.

@Epimetheus

Thanks, yes there is a connection indeed, how does this extend to QED?

Regards

Here's what Dr. Mills posted. Probably not as much information as you would have liked but you can always prod him for more detail on the forum.

Also GUTCP theorizes that excited states are due to photons expressing "effective charge" and shielding the electron to a degree from the central field of the proton. I guess if one accepts that a high energy photon can convert into an electron and positron the idea of photons in certain situations expressing effective charge isn't all that strange. I'm not sure how to relate this to K-capture but just thought I'd mention it.

Randy MillsToday at 5:12 AM
K capture can only occur if the reaction can form a more stable nucleus. A proton cannot undergo K-capure for example.

Mills states as follows:

Quote

Mills has trademarked “Hydrino.” And because his issued patents claim the hydrino as an invention, BLP asserts that it owns all intellectual property rights involving hydrino research. BLP therefore forbids outside experimentalists from doing even the most basic hydrino research, which could confirm or deny hydrinos, without first signing an IP agreement. “We welcome research partners; we want to get others involved,” Mills says. “But we do need to protect our technology.”

The insulator-metal transition in hydrogen

http://www.pnas.org/content/107/29/12743.full[/quote]

Very high temperature shock wave methods might make metalize hydrogen obtainable.

This transition from molecular liquid to atomic liquid is called the PPT (discussed below). Leif Holmlid uses a quantum mechanics process called Rydberg blockade to produce metalized hydrogen where a Rydberg matter substance like potassium is used as a QM template to reform the atomic structure of hydrogen into the low orbit based liquid matalized form.

Quote

https://en.wikipedia.org/wiki/Metallic_hydrogen

Shahriar Badiei and Leif Holmlid from the University of Gothenburg have shown in 2004 that condensed metallic states made of excited hydrogen atoms (Rydberg matter) are effective promoters to metallic hydrogen.*

* A phase of hydrogen Rydberg matter (RM) is formed in ultra-high vacuum by desorption of hydrogen from an alkali promoted RM emitter (Holmlid 2002 J. Phys.: Condens. Matter 14 13469). The RM phase is studied by pulsed laser-induced Coulomb explosions which is the best method for detailed studies of the RM clusters. This method gives direct information about the bonding distances in RM from the kinetic energy release in the explosions. At pressures >10-6 mbar hydrogen, H* Rydberg atoms are released with an energy of 9.4 eV. This gives a bonding distance of 150 ± 8 pm which corresponds to a metallic phase of atomic hydrogen using the results by Chau et al (2003 Phys. Rev. Lett. 90 245501). The results indicate that a partial 3D structure is formed.

I beleive that there are other theories that have been accepted by science that explain below base hydrogen orbits; specifically metalized hydrogen. High pressure physics is directed at producing metalized hydrogen as its major goal. [/quote]

All the experimental data that Mills has accumulated may very well be consistent with high temperature shock wave produced PPT hydrogen.

From Holmlid

Quote

Instead of inverted Rydberg matter, it is spin-based Rydberg matter with orbital angular momentum l = 0 for the electrons. It is shown to be both superfluid4 and superconductive (Meissner effect observed) at room temperature.6,7 The measured H–H distances are short, normally 2.3 pm.1,3,9 Several spin states with different internuclear distances exist.3 It is likely that the main process initiated by the impinging laser pulse is a transition from level s = 2 with H–H distance of 2.3 pm, to level s = 1 with theoretical distance 0.56 pm. At this distance, nuclear reactions are spontaneous and laser-induced nuclear processes are thus relatively easy to start.

@Epimetheus

I don't understand this connection, the radial solutions are essentially Laguerre polynomials + exponential for Shrödingers equation of hydrogene and
in the derivation you gave me he uses spherical bessel functions as a radial function. So I can't follow this line of thoughts. But it is true that the fourier
transform with spherical bessel functions for the radial part indeed fourier transform into Mills charge distribution.

Regards
Stefan

Has anyone worked through Appendix I to the point they feel comfortable with the derivations? I'm mostly OK with it (except for the discussion of the H() and G() functions). However, the conclusion uses some terms that aren't well explained. While I *think* I understand these, can anyone take a crack at providing a more intuitive justification behind the highlighted equations? Exactly what is represented by the cross-product s_n * v_n? Is omega_n the angular frequency of the emitted photon? I think s_n is the spatial frequency expressed in rad/m, and v_n is a velocity in m/sec of the current density. And radiation requires that the cross product of the two at some point on the orbitsphere is equal to the photon's wavelength. Am I understanding this correctly?

I think that in order to understand a proof of this you should in stead of the taken path, expand the plane wave in the fourier transform
into a sum of spherical bessel functions and spherical harmonics, the sum will cancel almost all terms but a single bessel and spherical
harmonic that match the same quantum number of the Mills charge distribution due to orthogonality. You will end up with the fourier transform being:

(*) j_l(|s|r) Y_lm(theta,phi)

Which is much better because the stated equation (38) in Mills takes convolution with all factors except the last having s. You just can't show that
this expression dissapears because of the property of the convolution. now for a specific w0 |s| has a certain magnitude for light like wave numbers
and hence r can be chooses so that (*) e.g. |s|r represents a zero of the spherical bessel function and (*) is shown to be zero for all light like s,w.

To understand everything that is written is hard though. In all to motivate the non radiation one only needs a half of page I think and could keep
it much much simpler than whats written in the book.

Regards
Stefan

To further explain and highlight that the key to proper mathematical understanding of Mills theory is the expansion of plane waves in various ways.

We have a photon inside the atom that is trapped. Consider the superpositioning of EM plane waves assume that the wave vectors of all the plane waves are evenly distributed e.g. they live on a sphere with constant radi. Again the theorem where you expand the plane wave in bessel function and spherical harmoics apply and we get the explicit solution of the electrical potential as

~ j_0(|r|w/c)exp(i w t), r = sqrt(x^2+y^2+z^2)

j_0(x) = sin(x)/x and hence |r|w/c = 2pi for a zero
<=> |r|2 pi f / c = 2 pi
<=> |r| 1/(1/f c) = 1
<=> |r| 1 / (T c) = 1
<=> |r| / lambda = 1
<=> |r| = lambda

So the lambda of the trapped photon has to be the same as the radi as described in option geeks post above.