That would be a possible way to do it. But that is not how it seems to be done in the report. The power in is calculated from "Energy input: V=0.1 R=1 Ohm → W=0.01" where V is the voltage over the 1 ohm resistor. Hence what seems to be calculated is the power in to the resistor. Not the power in to the QuarkX.
That is your misunderstanding, which is the same misunderstanding that THH has, in my opinion. There is a single resistive path. The two voltmeters are being used in a redundant fashion. They are measuring the voltage drop across a known resistance, then determining the power using one of the most basic and well-known laws. I don't even want to name it here, it is that well-known. THH is smug because he thinks I don't know what law it is, or how it is used. THH has no idea what my background is nor my education. He takes cheap shots and capitalizes on typos.
My success rate is quite high with my predictions. And I predict that the two voltmeters are measuring the same voltage drop across the total resistance of the single resistive path through the reactor. Let's see whether THH or I turn out to be right. My guess is--probably me again.