Mizuno : Publication of kW/COP2 excess heat results

Dreamers

AhiAhi - a one time event from trusted guys with replication efforts ongoing.

"a one time event ..."

Kirkshanahan.

"Your attempts to turn my safety concerns into a joke aren't really appreciated "

Thinskinned human.

You are not MARY but KIRK.

My ridicule was addressed to her/him not you... unless you are one and the same.

There are 3 mg of deuterium in the reactor.

This is about the minimum you can use to get a measurable effect.

This reactor is safer than my homemade natto

"I am talking now about metal hydride beds with 15 kg of alloy"

I can't recall reading that Mizuno used that in this paper.

Lighten up, bro

Quote from Alan Smith

Not according to Wikipedia...

Absolute humidity[edit]

Absolute humidity is the total mass of water vapor present in a given volume of air. It does not take temperature into consideration. Absolute humidity in the atmosphere ranges from near zero to roughly 30 grams per cubic meter when the air is saturated at 30 °C (86 °F).[4]

Absolute humidity is the mass of the water vapor {\displaystyle (m_{H_{2}O})}, divided by the volume of the air and water vapor mixture {\displaystyle (V_{net})}, which can be expressed as:

{\displaystyle AH={\frac {m_{H_{2}O}}{V_{net}}}.}

The absolute humidity changes as air temperature or pressure changes. This makes it unsuitable for chemical engineering calculations, e.g. for clothes dryers, where temperature can vary considerably. As a result, absolute humidity in chemical engineering may refer to mass of water vapor per unit mass of dry air, also known as the mass mixing ratio (see "specific humidity" below), which is better suited for heat and mass balance calculations. Mass of water per unit volume as in the equation above is also defined as volumetric humidity. Because of the potential confusion, British Standard BS 1339 (revised 2002) suggests avoiding the term "absolute humidity". Units should always be carefully checked. Many humidity charts are given in g/kg or kg/kg, but any mass units may be used."

Display More

Yeah, does make more sense to use the specific humidity... We are looking at mass flow after all.

Or to put it another way, I also need to consider the change density at inlet and outlet, if using absolute humidity figures.

I think this will change my calculated 19W maximum possible error (due to to a swing in air humidity) by about 10% - although I can't work out which direction it changes without a pen and paper.

Quote from bocijn

In Mizuno's controlled situation the excess heat power is of the order of 50W

I thought 100W?

Quote from maryyugo

Try reading what he (and I) have been written. Bro.

All I remember reading from your postings was something about UFO people and rectal probes.

...What is it with you and rectums?

Freudian field day...

Zeus45 said "I thought 100w"

Of the order of 10- 100W depending on the input, and how you define power.

Actually energy(MJ) ratio is what I use

DIY e.g Power input 248

Copy Fig 28. Into paint

Color it red and blue

Have some fun with pixels. upload to

http://www.geotests.net/couleurs/frequences_en.html I got red =121 blue=61(depends on your clipping)

I calculate average output power for the 30 ks is 327 KW

327-248= 79

XS average power = 79W..

Which is less dangerous than the 100W lightbulb in my natto incubator.

Xs Energy ratio is approximately 100%... COP 2??

Aha I see (great link).

...Or 79Ws/s as some like to say.

Edit: Although why 2000/3000?

Dewey,

Do you know the model number of the 5ppb Finnigan?

BTW: 5 ppb of what in what and how?

Zeus45,

Although why 2000/3000?

that's the problem with average power.. is the input defined to be over 20000, 30000.??

I was wondering if you could check the xs energy for Figure 26 for an input of 8.25 MJ

Using average temp =28.1, Hc =1006J/kg/deg, density =1.17 kg/m3, flowrate = (3.87 m/s , area 4.4/1000 m2?)

I got 11.8 MJ output.. xs = 3.55

I do not think humidity and temp variations make a significant difference.

Quote from bocijn

depending on the input, and how you define power.

Quote from maryyugo

There are alternative definitions of "power" in physics experiments?

Well there's instantaneous power and average power for two...

RobertBryant,

My way of looking at it is 4.96MJ (or 61 units) of energy go in and 121 units of energy come out... So... 4.96*121/61 = 9.84MJ out

9.48MJ/30000s = 316W average power out

Quote from bocijn

is the input defined to be over 20000, 30000.??

Maybe you could say 248*20000/30000 = 161W effective average power in

But It doesn't make much sense to me personally to compare the average powers if the time span is different... I'm not quite sure what it tells us that's more useful than looking at either the total energy or the instantaneous difference between POut and PIn.

Quote from bocijn

I was wondering if you could check the xs energy for Figure 26 for an input of 8.25 MJ

Using average temp =28.1, Hc =1006J/kg/deg, density =1.17 kg/m3, flowrate = (3.87 m/s , area 4.4/1000 m2?)

Where does the 8.25MJ and average temp = 28.1 come from?

Quote from bocijn

I do not think humidity and temp variations make a significant difference.

I agree.

The 8.25MJ is from the paper,, 100W x 82.5 ks

the 28.1 is the temperature that gives equal area above/below it in my previous "integral" area post

The 28.1 is a red herring, as to work out the average power output using Hc =1006J/kg/deg etc. you need to know average output temperature *minus* average input temperature.

But a faster way is just to say this would be proportional to the top yellow area, and compare that to the size to the control. (590/335)

So, as you say: 1.76x as much energy Out vs In

But because the time span is the same, I guess you could also say average COP is also = 1.76 over the whole experiment.

Quote from bocijn

I was wondering if you could check the xs energy for Figure 26 for an input of 8.25 MJ

I got 11.8 MJ output.. xs = 3.55

8.25MJ x 1.76 = 14.5MJ output... xs = 6.25MJ ?

Zeus 45". I'm not quite sure what it tells us that's more useful than looking at either the total energy or the instantaneous difference between POut and PIn"

Energy (MJ )ratios are more useful for me.

Currently the price here for me in NSW is 4.5 cents per Natural Gas Megajoule and 9.4 cents per Electricity Megajoule.

Mizuno knows that he has to get the COP way up over 300% for this thing to be attractive.

at 200% it is not even breakeven.

For the 248W case the electricity cost of 4.96 Megajoules in is 46.6 cents

The output heat energy of 9.8 MJ could be supplied by gas at 44.1 cents .

Thanks.

The control/inactive input energy calculates as 7.15 MJ = (100Wx71.5ks)..it was run in for a slightly shorter time than for the active reactor.

The use of the average temp of 28.1 does account for some of the variation with density of the temperatures in and out

( there is not much Hc variation )

But the calculation is done much more accurately in the spreadsheet calculations, over 3485 time points, with the use of actual in/out temps in the enthalpy calcs

rather than average temperatures.

This is just a roughasguts way to look at how much Xs there is

Roughasguts energyout/energyin for 120W, shortime(~21 kilosecond ) power input.

Brown/blue areas are artefacts of Excel chart. Black trend lines are the actual temperatures.

COP = 1.14. Xs heat =14%.