The gyroscopic electric central

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    We have to imagine 2 axes of rotation: the axis of rotation of the wheel that we identify with the code 55, and the axis of rotation of the handlebar that we identify with the code 57.

    Having ascertained that the rotation axis 55 does not rotate, that is, it performs zero revolutions per second, we make a steering of the handlebars to the left or right, so for a moment the rotation axis 57 rotates. Steering with the wheel stopped that is accelerating the axis of rotation 57, we realize that our muscles have to do some mechanical work.

    That mechanical work is caused by ...

    1. Acceleration of the wheel mass (the rotation axis 55 is always stopped).
    2. Acceleration of the handlebar mass.
    3. Air friction.
    4. Tire friction on the asphalt.


    We realize that muscular effort is not small because the friction of the rubber on the asphalt is big.

    We want to remove the friction of the rubber on the asphalt, to do so we have to lift the front wheel of the bicycle and then fix an iron beam that keeps it lifted permanently.

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    We repeat the work to steering left or right, and we realize that muscle strain is less because the friction of the rubber on the asphalt has been removed.

    Now that mechanical work is caused by ...

    1. Acceleration of the wheel mass (the rotation axis 55 is always stopped).
    2. Acceleration of the handlebar mass
    3. Air friction.

    Now we mount a wheel on a drill and place the wheel on the front wheel of the bicycle, therefore the front wheel of the bicycle begins to accelerate until it reaches a high speed, for example 2000 rpm.

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    We repeat the work to steering left or right, and we realize that muscle strain is greater than before when the front wheel was stopped.

    Now that mechanical work is caused by ….

    1. Acceleration of the wheel mass in accordance with the rotation axis 57.
    2. Acceleration of the handlebar mass.
    3. Air friction.
    4. gyroscopic effect

    Lifting the wheel and turning it, we replaced the friction of the rubber with the gyroscopic effect.

    In theory, if the wheel does one million rpm, it would be impossible to steer, not even the strongest man in the world could steering.

    It is possible to consider that bicycle front wheel as if it is a flywheel.

    There are no doubts: the angle of an axis of rotation of a flywheel tends to remain fixed in space.

    We want to design a mechanism that exploits this trend.

    How you do it ?

    It is not easy to design it because if an object has a tendency to move, it is easy to exploit its energy because I connect that object to the pivot of an electric generator and produce electricity, but in the case of the gyroscopic effect the situation is inverse because the object wants to stay still.

    It is paradoxical! ... We are very demanding and we want to get kinetic energy from something standing still.

    Although the object wants to be still, we have to show that it wants to move, so the world has to turn around it or at least a small part of it..

    I connect the handlebars of that bike to a
    dynamo, and then I make sure that the floor turns on itself; but we must not be
    stupid to turn the whole floor for real, it is enough to turn only the stator
    of the dynamo.

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    But even in this way we have not get anything because the energy produced by the dynamo is equal to that which we have to spend to power the engine, indeed the energy produced is lower because there are the inevitable losses caused by various friction.


    In other words, the mechanical twist to turn the stator of the dynamo fully discharges on the electric motor.

    It's still not good: we have to design a mechanism in which the mechanical torsion of the stator of the dynamo must not be discharged on the engine.


    The idea is to multiply so many things for two: 2 dynamo, 2 bicycle wheels, 2 dumbbells.

    But the engine is only 1 so the engine is an exception to the rule.

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    By doing so, the mechanical twists of the dynamo stators are not in opposition to the motor, in other words the motor turn effortlessly as also the motors which have a rotation axis of 55 and 56 turn effortlessly.


    An engine that turn effortlessly anyway absorbs some energy because there are the inevitable frictions.

    It is during the start-up of the engines that there is great absorption of energy, at that moment there are not only the frictions, there are also large masses to be accelerated up to the speed of the regime.


    There remains the technical problem of how to bring energy to the engines and take energy from the dynamo, not easy to solve this problem because everything is rotating, everything is spinning, and would need a "super collector" that we could also call "super distributor".

    If we consider that it is important to understand the physical principle then the technical problems of super collector are of secondary importance and an engineer will have to solve the technical problem of secondary importance.

    Here is an example of a super collector or distributor, but the dynamos have been replaced by alternators so the wires that come out are 3 and not 2.




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    (translated by google)

    IDENTIFICATION CODES

    1,2,3,4) flywheel

    5 and 6) three-phase alternator

    7,8,9) electric motor continuous voltage

    10) thrust bearing

    11) collector and support base for alternators

    12,13,14,15,16,17,18,19,20,21,22,23) graphite brush

    24) cover

    25) ball bearing

    26.27,28,29) bolt

    30,31,32,33,34,35,36,37,38,39,40,41,42) tube of plastic that is electrical insulating

    43,44,45,46,47,48,49,50,51,52,53,54) tube of copper that is electric conductor

    55,56,57,58,59) imaginary axis of rotation

    60,61) voltage elevator transformer

    62,63) high voltage pylon

    64) voltage reducer transformer

    65) Graetz bridge rectifier

    66) manual switch

    67) starting accumulator

    68,69) washer

    70) resistor

    71) relay contact delayed to 5 seconds excitation


    ------------------------------------------

    By closing the switch 66, continuous electric voltage arrives at the graphite brush 19 and also to the motor 9, so the motor 9 starts to accelerate the base 11.

    From the graphite brush 19 electrical voltage arrives to the copper tube 50 which connects the electrical voltage to the graphite brushes 20 and 22.

    All brushes have a small spring whose purpose is to hold the brush against a copper tube, but for simplicity in the design the small springs have not been drawn.

    When electric voltage is reached at the brush 20, the electric motor 7 starts to turn and then the flywheels 1 and 2 turn.

    When electric voltage arrives at the brush 22, it happens that the motor 8 starts to turn and then the flywheels 3 and 4 turn.

    All four flywheels 1 2 3 4 are of heavy solid steel.

    Because of the gyroscopic effect, the imaginary rotary axes 55 and 56 have the tendency to maintain the same angle in the space around them, it follows that if the base 11 is rotating, the rotors of the alternators 5 and 6 are forced to turn. producing electricity which is sent to six copper tubes which are 43,44,45,46,47,48.

    The three copper tubes 43,44,45 feed the voltage transformer 60, instead the three copper tubes 46,47,48 feed the voltage transformer 61.

    The secondary circuit of the elevator transformers is connected to the high voltage cables, this is normal as in all power stations.

    It is already known that any electric motor in continuous needs at least 2 wires, in one wire the electric current and the other is considered by convention the return of the current, the copper tube 49 collects the return electric current and then complete the electrical circuit.

    Since the mass of the base 11 is noticeable with respect to the rated power of the microscopic motor 9, it is necessary to complicate the electric circuit so as to ensure that the starting electric current is limited; to do this there is the electric resistance limiter 70 and the delayed relay 71 normally open.

    By closing the circuit by means of the switch 66, the delayed relay does not close immediately so the electric current is forced to pass through the electric resistance limiter, but after about 5 seconds, the delayed relay 71 short-circuits the electrical resistance 70 and then arrives on the motor 9 full tension.

    By mistake there could be an obstacle that blocks the base 11 and therefore the motor 9 so unfortunately the relay gives the consent even when it should not, in this case an automatic thermal protection switch must intervene to avoid burning the motor winding 9.

    Instead of the delayed relay, a revolution counter could be placed; the tachometer is safer but it also costs more, or instead of the delayed relay you could put a watt regulator that excludes the resistance only if the number of revolutions exceeds a certain predetermined value.

    There are numerous methods to soften the start of an electric motor, but there is no willingness to explain them all.


    The imaginary rotational axes 57 and 58 rotate in the opposite direction to the rotation axis 59, it has not importance which direction the motor 9 rotates, but if by looking at the top we decide that the motor 9 must rotate clockwise, the rotors of the two alternators will turn counterclockwise.


    As a consequence both the alternator stators will suffer an anti-clockwise mechanical twist which will be released on the base 11.

    It will be unloaded on the base 11 because the alternator stators are bolted onto the base 11 by means of the bolts 72,73,74,75.

    It is very important to take into account the mechanical twists acting on the base 11 and the direction of rotation of those twists.

    The resulting vector of both counterclockwise twists will result in a total central mechanical twist whose rotation center is precisely the rotation axis of the motor 9, so the motor 9 is privileged by those twists and there is no contrast as is normal to think .

    The motor 9 is pushed by 67 and is also driven by the mechanical twists generated by the stators of the two alternators.

    The two mechanical twists are in one sense and by reaction the whole base is accelerated in the opposite direction, this is the basis of the principle of classical physics according to which every action corresponds to an equal and opposite reaction.

    The law of action and reaction favors the engine 9.

    This means that after the start-up period, the engine 9 could also function as an electric generator.

    The flywheels 1,2,3,4 must perform many rpm per minute, minimum 2800 rpm if it is possible to do 28 thousand rpm is better, without exaggerating too much otherwise the steel of the flywheels will deform due to centrifugal force.


    instead the engine 9 can turn slowly, 60 rpm per minute are sufficient but even 30 rpm are sufficient


    The flywheels 1,2,3,4 are the most important components, all the other components are of secondary importance, if those 4 flywheels are still, even all the other things stop.

    The 1,2,7 components represent the first gyroscope, and the 3,4,8 components represent the second gyroscope.

  • --- begin calculation ---

    Pa7 = power absorbed by the motor 7 at steady speed that is after starting the engine 7

    Pa8 = power absorbed by the motor 8 at steady speed that is after starting the engine 8

    Pa9 = power absorbed by the engine 9 at steady speed that is after starting the engine 9

    Pe5 = power delivered by the alternator 5 when fully operational that is after starting the alternator 5

    Pe6 = power supplied by the alternator 6 when fully operational that is after starting the alternator 6

    Pe5 = Pe6

    Petot = Pe5 + Pe6

    Petot = 2 * Pe5

    Petot = 2 * Pe6


    friction7 = loss of power due to the friction of the bearings inside the engine 7

    friction8 = loss of power due to friction of the bearings inside the engine 8

    friction9 = loss of power due to friction of the bearings inside the engine 9

    friction7 = friction8


    Pa7 = friction7

    Pa8 = friction8

    Pa9 = friction9


    Pe5 > [(Pa9 + Pa7) * 10]

    Pe6 > [(Pa9 + Pa8) * 10]


    Petot > {2 * [(Pa9 + Pa7) * 10]}

    Petot > {2 * [(Pa9 + Pa8) * 10]}

    --- end calculation ---


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