Calculating COP

COP, no idea from that, but the derivative i.e. dt/dT would show better what happened; here is a quick graph of that with a 15 samples (seconds) rolling average.

An event that lasted a few minutes transiently slowed down the exponential temperature decline normally expected for a standard resistor. After that, temperatures declined as expected; possibly slightly faster compared to null due to the gas contained inside the tube increasing thermal conductivity.

Quote from JohnyFive

Hey there!

I am running one experiment and I can find quite interesting results. Fuel is mixture of many elements.

Take a look at the attached plot and data. Could you calculate COP from this?

Measurement was made by IR gun that logged the temperature. You have to just ignore step around 200 deg C. This is measurement error (wrong E) and apply for both plots.

In both runs everything was same except the red plot - reactor has no Hydrogen inside - vacuum. Next comparison must be done with Argon.

What you can see is basically 600W of applied power at the heater -- identical for both cases -- and the power was cut completely. Before cut the power was stabilized and temperature equilibrated.

You can see Heat after Death for 30 minutes. There was no insulation whatsoever but with some wool around it could last few times longer

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What result would you get if you integrate both curves? Isn't the area below the curves a measurement for energy?

If yes then excess energy would be:

excess energy = area of blue curve - area of red curve

Quote from can

COP, no idea from that, but the derivative i.e. dt/dT would show better what happened; here is a quick graph of that with a 15 samples (seconds) rolling average.

I think the derivative i.e. dT/dt only shows how steep the temperature curve rises or falls (pitch of temperature curve), but this no real indication for the energy.

gerold.s

Rather than energy calculations (which I have not attempted at all) my graph was intended for better understanding what might have possibly occurred in the reactor. I was curious myself and I shared the result in this thread.

I wonder if JohnyFive is obtaining a figure of 1.2 by doing something like:

Σ(T_Active⁴) / Σ(T_Null⁴)

In this way (using Kelvin temperatures) I'm obtaining 1.22

That's basically pretending that the temperature recorded is an average value for the entire reactor in order to integrate the pseudo-power/energy obtained for every second in the data with its fourth power.

@JohnyFive

What brand/model is your IR gun? I am interested in one that can be used for both measuring and logging temperatures like yours.

Alan Smith

I don't have any real reason to wait for photos, just a few words would be fine.

I'm mostly curious because all affordable IR probes I've come across recently don't seem to have data logging capabilities or USB output and I was interested in getting one for quick tests (with all possible caveats considered due to emissivity issues, etc). If I have to spend in the few hundred euro range just to have this feature which could be very cheaply added by the manufacturer, then the money will be most probably be better spent elsewhere, at least on my part.

Alan Smith

Ideally one would need to know in advance which ones offer such relatively easy way to get temperature values as in the link above. I suspect many of the cheap models I have considered getting might not have such guarantees. Thanks for the possible suggestion, though; worth considering when I'll decide to also get an Arduino or similar experimental board to play with.