Mizuno reports increased excess heat

  • The equation that calculates airspeed from blower power (3) is given by Mizuno in the patent that Ahlfors helpfully posted.


    I do not understand the equations for power (1) and (2), however (3) seems straightforward.


    I wonder how well (3) corresponds to the data we actually have? The exact equation is given here.


    EDIT: this looks like it must be a different system from that described in the 2018 paper: 5W in the paper delivers ~5m/s air speed whereas from this equation 5W delivers 3.9m/s air speed.


  • Say for example the active reactor was in direct line of sight of the RTDs measuring air outlet temperature

    Maybe there is a 4d perturbation of space in LENR that allows light to go through two layers of aluminium foil


    In addition , by parabolic focussing geometry

    the blower with >>4m/s airflow speed cooling it heats up to 80C

    (while the rest of the calorimeter box is at <50C)

    radiates geometric heat to the outlet RTD.


  • 1) I guess someone else decided you said it was a "random" number. That person was confused as to what you meant.


    2) Trying to guess the quanti-sized voltage and current from this data series is a total waste of our time, i.e. like solving a meaningless puzzle or playing solitaire. Either Mizuno should give us this information, or we should just move on. Hopefully he will provide the data. There is real work to do here. The replicators data will come in soon. Rest up because this will heat up real fast.


  • The patent provides information that was not in the papers. Good find.


    Note: the mathematical formula using exp(-Wb/w) _may_ be approximated with the linear function that I got from regression over a relatively small move (the 49 points range) in power -- I will have to work on that to prove it. My point is the exponential function is not _necessarily_ inconsistent.


    With regard to Jed bringing in more digits -- the linear regression will still solve for something that will be VERY similar. I doubt the extra dights are significant and because regression is a robust numerical technique, the conclusion will not change over the relatively small range provided in the 49 points.


    If Jed gives us the entire spreadsheet (not here) we can then fit the exponential using a regression of the log, or similar numerical technique. No big deal here -- nothing to see. This is all normal and our guess was right as proven by the patent.

  • I don't understand the X60 adjustment? Could you possibly explain it?


    I don't understand that either. Maybe it is some limitation of the HP gadget? In other cases, there is an adjustment I understand, such as for a 3 ohm resister.


    I think those are the raw voltage number coming into the HP unit. I used to have one like that. You can program it to convert voltage to various common units such as degrees Celsius. You can use a conversion factor or a lookup table. It has all kinds of great features. 1980s technology at its best. Most HP instruments are wonderful.

  • Note: the mathematical formula using exp(-Wb/w) _may_ be approximated with the linear function that I got from regression over a relatively small move (the 49 points range) in power -- I will have to work on that to prove it. My point is the exponential function is not _necessarily_ inconsistent.


    Well, it gives the wrong answer. Aside from that, it is pretty good.

  • Well, it [the regression] gives the wrong answer. Aside from that, it is pretty good.


    Depends on what wrong means. If being able to predict the dependent variable for the data set to within 5 decimal places, it works perfectly as described by the standard deviation of its error.


    That a linear function can approximate an exponential that was hidden from view is not surprising. I will endeavor to verify this and report back.

  • Such questions as THH, Ascoli raise are OK, if we see only about 20-30% excess heat and have a low COP.


    If you are used to cook in a kitchen then you very well know the difference

    Richtig Jurg

    I conducted some Doyoubi no Daidokoro no kenkyuu this morning


    I applied the Japanese Tamagoyaki method to test if the blower could get up to a temperature of 80C.


    The blower got up to only 33 C on the lowest blower flowrate.

    which is

    approx. 100 cu.m/hr

    based on an S-Pitot tube

    traverse.


    To test the heat output of Kambrook Reactor

    I conducted the "GekochtesWasser " test.

    500g. delta t= 28C, 2 min. Heating rate = 488 Watts


    Solder test showed reactor surface temp was > 221C.

    No RTD , but the glass thermometer could have

    been heat affected and had a stroke?


    Kagemusha yori.

  • The text in that patent will be in an upcoming paper. I have no idea when it will up-come. It takes anywhere from six months, to six years, to never.


    Jed; the section I posted above has a number of serious errors: equations (1) and (2) (time integration does not make sense in context of power, and energy is not used elsewhere). Also sentence mentions dT which is not used (dt is, in the integral, but that is obviously time not Temperature). So it would not a lot of careful checking.


    THH

  • I don't understand that either. Maybe it is some limitation of the HP gadget? In other cases, there is an adjustment I understand, such as for a 3 ohm resister.


    I think those are the raw voltage number coming into the HP unit. I used to have one like that. You can program it to convert voltage to various common units such as degrees Celsius. You can use a conversion factor or a lookup table. It has all kinds of great features. 1980s technology at its best. Most HP instruments are wonderful.


    Difficult to understand how you get X60 - this might be seconds to minutes etc, but that does not make sense here. Voltage measured over R as proxy for current would mean a resistance of 0.0167 - which is not an E24 value. I guess it could be a homebrew 1/60 potential divider on the voltage measurement, but that is a weird division factor to choose.


    I'd want to understand this further before being able to interpret those figures.


  • RB - I'm in awe of this experimental effort.


    But it does not properly answer the question. Too many variables. Looking at it naively:


    The radiative forcing from 380C vs 22C is (683/494)^4 = 3.65


    If we suppose Tamb = 20C, so deltaT=13C, that would scale to 67.5C at Treactor=380C.


    But as I say there are too many other variables.

  • Sorry!! Do you really expect something else ?? The speed is given by input wattage and ergo the energy (air flow speed) must reflect it, if the efficiency of the motor is not varying .


    Wyttenbach:


    If you read my earlier posts you will have the context here.


    ascoli's clever observation shows that the airspeed figures for these tests are calculated from blower power, as measured, using the calibration graph given in the paper, rather than measured with the hot wire anenometer.


    This is not surprising, not improper. However it was not clear, without ascoli's analysis, from the paper. A reader might more likely think that the airspeed shown was directly measured.


    As I pointed out this is not a big deal, it makes mistakes more likely is all, and it should be explicitly mentioned.

  • Depends on what wrong means. If being able to predict the dependent variable for the data set to within 5 decimal places, it works perfectly as described by the standard deviation of its error.


    The problem is that spreadsheets are all more precise than than 5 decimal places, and this one shows different answers than yours. So you got the wrong answer. If the function you wrote here gave the right answer, it would agree with Mizuno's numbers to more than 5 decimal places.

  • ascoli's clever observation shows that the airspeed figures for these tests are calculated from blower power, as measured, using the calibration graph given in the paper, rather than measured with the hot wire anenometer.


    No, it does not show that. Not if you understand grade school arithmetic. Ascoli claimed the blower power is multiplied by one factor to produce the air flow. If that were true, you could divide air flow by blower power and the get the same answer every time (the factor). Here, let me spell that out, so that even you and Ascoli understand:


    A * B = C. To solve for B, divide C by A. Example: 2 * 4 = 8. 8 / 2 = 4.


    Do you understand?


    As you see in the table I uploaded, the actual data does not show the same factor in every case. Ascoli should have tried that himself before uploading a blatant error.


    Do you understand this? It is 4th grade arithmetic. Are you deliberately repeating this as a lie, or are you incapable of doing 4th grade arithmetic?


    After Ascoli came up with this, other people tried to develop equations with more than one factor. They failed. Any spreadsheet works to better than 5 decimal places, and no one has come up with a function that converts blower power into air speed. I am sure you cannot come up with one either.


    Why do you make claims that anyone with a grade school education can see is wrong? Are you trying to fool people here? Do you have no respect for the audience here?

  • Ascoli claimed the blower power is multiplied by one factor to produce the air flow.


    I've never said this. This is what I said in my previous comments


    From my comment Mizuno reports increased excess heat

    That diagram reveals that the air speed is clearly derived from the blower power throughout a mathematical formula.

    From my comment Mizuno reports increased excess heat

    This fact demonstrates that the values of the Air Speed were calculated starting from the above Blower Power values!

    You can find such a formula to convert the Blower Power (in W) into Air Speed (in m/s) on the "AP" column of the spreadsheet of the 120 W active test run on May 19, 2016 (3). A similar formula, or maybe the same, was used to calculate the Air Speed in the 100 W control test diagram published in (1).

    (1) Mizuno reports increased excess heat

    (3) Mizuno : Publication of kW/COP2 excess heat results


    From my comment Mizuno reports increased excess heat

    - Air Speed was obtained mathematically by using a formula which fits the curve shown in Figure 4 of (3). This formula is probably similar to the exponential relationship shown in the formula (5) described at page 14 of a 2017 paper (4). However, due to the very narrow range of the 49 data sample provided by JR, the exponential relationship between BP and AS is undistinguishable from the linear one that you have proposed.

    (3) http://lenr-canr.org/acrobat/MizunoTincreasede.pdf

    (4) https://www.lenr-canr.org/acrobat/MizunoTpreprintob.pdf

    ...


    As you can see, I never claimed that "the blower power is multiplied by one factor". Instead, I talked about a formula, in particular an exponential relationship such as that contained in the 2017 Mizuno's paper and in the 120 W spreadsheets that you have published here on L-F and on Vortex. This semi-empirical relationship contains 3 parameters.


    You said (a), that you have the complete spreadsheet containing the data of the test under discussion with "extensive notes on every field". If you look carefully to these notes, you will probably find that formula and the values of the 3 parameters. Please, let us know these values.


    (a) Mizuno reports increased excess heat

  • Looking at it naively:


    The radiative forcing from 380C vs 22C is (683/494)^4 = 3.65


    If we suppose Tamb = 20C, so deltaT=13C, that would scale to 67.5C at Treactor=380C


    The THHnew radiative forcing calculation is in error because of the omission of the area variable

    and because the model is wrong. The reactor emits and receives radiation from box..

    It does not receive and emit radiation from the ambient directly.


    One CANNOT model the heat transfer this way.,,its just wrong.

    One needs to take into account the area of the reactor and the area of the box.

    The box area at 2m2 is ten times the area of the reactor at 0,2 m2

    The emissivities differ, reactor ~ o.2... box ~o,o4.. There are three variables involved,, not one.

    Area ,Emissivity and T.


    Heat radiated = constant x Area x Emissivity x T4 .. The 67.5C calculation is meaningless.


    The real situation is much more complicated as the convective exchange to the air exiting the box

    does not increase linearly with temperature

    because the convective currents within the box get stronger with temperature.

    In addition we cannot assume emissivities stay constant with temperature

    For example btw 240 and 380C the emissivities of stainless steel decrease by 10%.

    In addition there is no guarantee that Stefan's T4 dependence holds strictly

    when the reactor surface may be affected by strong magnetic fields.


    It is better to do an experimental model with a cooktop as I have done.

    A 488W input to the 0.027m2 cooktop results in a surface temperature of about 500C,

    This compares with the 295W output of the Mizuno reactor giving 380 C.

    Yet with the hotplate at 500C , the blower body only situated 20cm above the hotplate only gets to 33C


    I would suspect from these results that in the R20 expt ..the blower body never gets higher than 40C

    which replicators can verify. The convective air currents cool the blower

    to less than the adjacent box regions because of the higher air velocities in the blower

    The THH indirect - heat- radiation- to -the- RTD hypothesis is groundless.

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