MIZUNO REPLICATION AND MATERIALS ONLY

  • I scrounged up a 12V, 0.1 A brushless fan about 4 x 4 cm, and not knowing where best to put it, installed it in the intake pipe, blowing in. Hooked to the outlet fan power supply, the fan uses less than 1 W. The outlet fan only increased in speed 10 RPM, so the outlet velocity is barely affected.


    Anyways after some tests, pointing the intake fan downwards into the calorimeter box at a 45 degree angle reduces the cycling outlet temperature from +/- 0.4 C to +/- 0.15 C

  • Paradigmnoia


    A few years ago I read an old book about wind-tunnel design, written in the 1930's when they were just beginning to get to grips with the technology for wind speeds speeds of !00 mph+. It struck me at the time that it is amazingly complicated and very prone to producing artefacts which the designers (and perhaps you?) often found to be counter-intuitive and thus hard to understand.


    It occurs to me reading the above, that I should get out more!

  • Paradigmnoia


    A few years ago I read an old book about wind-tunnel design, written in the 1930's when they were just beginning to get to grips with the technology for wind speeds speeds of !00 mph+. It struck me at the time that it is amazingly complicated and very prone to producing artefacts which the designers (and perhaps you?) often found to be counter-intuitive and thus hard to understand.


    It occurs to me reading the above, that I should get out more!

    It seems as though there is cyclical detachment of the hot air stream coming off of the heater. The typical outlet temperature cycle (without modification) is about 2 minutes long. With the tiny inlet fan blowing in the best position found so far, the sinusoidal temperature cycles are reduced to about 15 seconds long. It seems odd to me that the hot air blobs can even hang together at all inside the box with the inlet air rushing in. I tried incense smoke to see what goes on inside, but it is not thick enough and dissipates too quickly. I am not too enthusiastic about home made smoke formulas (I know a few) being used inside. If I can scrounge up enough pipe to vent outside I will probably try the recipe that uses sugar.

    .

  • Magicsound. I'm curious as to your next steps and tests with your setup.


    I've finished the fabrication and assembly of the MR3 cell, and successfully baked it out to 8E-6 Torr (very good!). I discovered a leaking valve in the gas manifold during the first D2 soak, and will be dealing with that in the next few days. So calibration should be possible this coming week, then disassembly to install two already prepared meshes, and bake out again. If all goes well, MR3.1 with Deuterium should begin in a week.

  • Desireless is claiming he has made

    a successful Mizuno replication

    on ECW.


    https://e-catworld.com/2020/06…nr-experiment-desireless/


    We do have a new report of 2 more successes in addition to Desireless. They are both Japanese companies, one getting COP1.5. With the lifting of restrictions, Mizuno and his team have become very active. They arranged for Zhang to work with one of the European replicators. 10 reactors are being readied to ship for others to use, including one for our Alan S. Commendable considering Mizuno's wife is being treated for cancer.


    Things are moving again thank goodness. If Magic sees signs of LENR, I think that could stir the field up, and many more serious replicators will jump on the bandwagon.


    Edited to be more accurate.

  • After fully cooling, the cell pressure had increased from 305 Pa to 343 Pa. So there is still some leakage after cleaning the sampling valve. I've ordered a diaphragm-sealed valve that is better suited to retaining Hydrogen, and that will be installed before the next calibration. Please stand by....

  • Unfortunately it appears Desireless is another replicator that has discovered the high thermal conductivity of Hydrogen/Deuterium and confused it as excess heat. Desireless is measuring external reactor temperature with and without Deuterium for a constant input power and is interpreting increased external reactor temperature when Deuterium is introduced as excess heat. What it appears they are observing is just the high thermal conductivity of the Deuterium increasing the heat conduction to their measurement location. You need a calorimeter for these experiments or at the very least you have to be as meticulous as magicsound .

  • Desireless is measuring external reactor temperature with and without Deuterium for a constant input power and is interpreting increased external reactor temperature when Deuterium is introduced as excess heat. What it appears they are observing is just the high thermal conductivity of the Deuterium increasing the heat conduction to their measurement location.


    If the temperature is measured on the outside wall, and if you wait for it to stabilize, then the internal conductivity make no difference. The outer wall will come to the same temperature no matter what. With highly conductive gas, it will reach this temperature quickly. With less conductive gas, it will take longer. The final temperature of the outside wall is a function of the power level and the total area of the outside surface only. No other parameters affect it.


    The temperature inside the reactor, at the center, will vary depending on gas conductivity. Less conductive gas will make the temperature higher, after the terminal temperature is reached.

  • If the temperature is measured on the outside wall, and if you wait for it to stabilize, then the internal conductivity make no difference. The outer wall will come to the same temperature no matter what. With highly conductive gas, it will reach this temperature quickly. With less conductive gas, it will take longer.


    Let me add that if that were not the case, you could make a perpetual motion machine. Suppose you can bring the surface temperature of two identical cylinders up to two different temperatures with same input power to both. You can then have heat flow from the hotter vessel to cooler one, to run a heat engine, that powers both of them.


    In other words, if the temperatures are different, with the same surface area, more heat has to be radiating from the hotter vessel.



    A hotter surface with the same surface area MUST mean there is more energy. A hotter inside temperature may well be because the insulation is better, where the insulation in this case is the conductivity of gas. Less conductive gas is like putting a heavier blanket over yourself to stay warm in winter, with the same body heat (~100 W while sleeping; basal metabolism). The outside of the blanket is the same temperature no matter how thick or thin the blanket is. YOU are warmer; the blanket surface is not.

  • Unfortunately it appears Desireless is another replicator that has discovered the high thermal conductivity of Hydrogen/Deuterium and confused it as excess heat. Desireless is measuring external reactor temperature with and without Deuterium for a constant input power and is interpreting increased external reactor temperature when Deuterium is introduced as excess heat. What it appears they are observing is just the high thermal conductivity of the Deuterium increasing the heat conduction to their measurement location. You need a calorimeter for these experiments or at the very least you have to be as meticulous as magicsound .


    Here is what Desireless responded on ECW:


    "Of course there was calibration performed. Actually there were multiple calibrations, including with very same deuterium pressure. Actually multiple pressures to make sure I can run with the mesh at a different pressures.

    Later on after excess heat results were clear the mesh was removed to re-run calibration. And it is matching with the original calibration. And of course there were measurements from all sides of the reactor. This work was done in a half year or so.


    Interestingly internal pressure is not playing that important role, since surface temperature is different only by not more than 5C in pressure range from 0.001 - 0.1 Bar. Moreover behavior you can see at the plot can't be reproduced without activated mesh. You will not see temperature bump followed by a slow decrease."

  • If the temperature is measured on the outside wall, and if you wait for it to stabilize, then the internal conductivity make no difference. The outer wall will come to the same temperature no matter what. With highly conductive gas, it will reach this temperature quickly. With less conductive gas, it will take longer. The final temperature of the outside wall is a function of the power level and the total area of the outside surface only. No other parameters affect it.


    The temperature inside the reactor, at the center, will vary depending on gas conductivity. Less conductive gas will make the temperature higher, after the terminal temperature is reached.


    JedRothwell what you say is true, but Desireless didn't wait for it to stabilize. The plot he has shared covers a period of 20 minutes. If his reactor is anywhere near the mass of Mizuno's then it takes hours for it to stabilize. You can see it starting to head back toward equilibrium in the tail of his plot. Even in the steady state the temperature distribution will change when Deuterium is added. In vacuum much of the heat is conducted out through the heater support resulting in the heater supporting end of the reactor being relatively warm. Once Deuterium is admitted the heat distribution will change to be a more consistent temperature over the surface of the reactor. I think you agree that this makes it very difficult to use temperature only as a measurement of excess heat. You have to do calibrations with multiple temperature measurement points at each Deuterium pressure and wait hours at each power step. If Desireless would like to publish these calibrations and full pictures of his setup as others of us have then I might take his claims more seriously.

  • The outer wall will come to the same temperature no matter what.

    That would be true (in time) only if the outer wall was not losing heat to the outside.

    But because it is not a closed system, and because it is losing heat to the outside, the same wall temperature can't be achieved. The result will be two different equilibrium temperatures for the outside wall, and two different internal temperatures for the core.

  • If Desireless would like to publish these calibrations and full pictures of his setup as others of us have then I might take his claims more seriously.


    I would be surprised to see a full disclosure. Desireless also goes under the pseudonym me356, and JohnyFive as Alan S alluded to earlier. The storyline is the same with each: they claim success, and after stringing us along for a time, they are eventually challenged to show the raw data, and photos. Many promises and excuses later, they disappear.


    We banned the avatars Desireless and JohnyFive to prevent confusion, but kept me356 active. He is more than welcome to show himself, and explain his latest "success".