My advice is to just go ahead and test your rig, you never know what can happen. I would experiment with using different metals as electrodes if I were you. You could also try to bounce the electrodes against each other in a hydroxide solution to see if you get unusually bright light ( see Simon Brink experiments). The guys of the ohmasa gas use D2O though, can get pricey.
You could use Alan's muon generator for your muon source. You will get about 1 GeV per particle. I would change the design of Alan's Meshsugganon generator to enclose the particle generating core with a magnetic bottle which will direct the sub atomic particles which will radiate in a spherical distribution into your muon energy capture mechanism. If you surround the Meshsugganon generator core with lots of lead over a foot thick, you should get 200 fusion events per each muon created. The lead should shield the gammas that the fusion reaction generates.
For the diagram of the Meshsugganon generator see post as follows:
I will try to use it with Holmlid's/Kotzias set up. Not sure what to expect but I will give this a go.
I actually was going to drop the idea but they address the issue of surface muon flux. From the patent : Electricity from muons good patent.pdf (from the US patent office, this one gives more details).
"The order of magnitude of muon flux at the earth's surface is about 10−4/m2·s and therefore, the flux of muons is negligible. For example, to achieve a power of 760 kW (equivalent to 4, 7·1015 eV/s), considering that each muon has an energy of 4 GeV, it would take a flow of the order of 1015 muons/s. To compensate for said negligible flow, it would be necessary to increase the capture area of muons with coils of areas equivalent to the area of several cities, which would be totally inviable. Nevertheless, and very surprisingly, the device according to the present invention can capture a sufficient number of muons to enable a realistic extraction of muonic energy from the air and is highly economical in an area of less than half a square meter. Without being limited to a probable physics theory, it is believed that the explanation is as follows:
A magnet has “closed” and “open” field lines, which form an angle Θ between them tending to zero. Likewise the magnetic field from the primary coil of the muonic generator according to the invention also has both types of magnetic lines. Thus the “open” field lines propagate to high altitudes including the region of the formation of muons, at an altitude of 10 kilometers, forming a magnetic funnel whose top “opening” can have a radius of dozens of kilometers. It is these lines that will collimate atmospheric muons into the coil of the generator of the present invention, whose diameter is for example only a few centimeters. Thus, the magnetic field of the coil acts as a muon drain, which is oscillating in time. This frequency of oscillation of the field has a wavelength λB that is a fraction multiple of the Compton wavelength of the muon λC (λB=n·λC=n·5, 88×10−23 m) so that the energy of the magnetic field used in the captation process is reduced as much as possible and is selective of muons only. The whole process above applies in cases in which the coil of the muonic generator presents its axis horizontally, vertically or at any angle between these."
I did not see any mention of superconducting magnets.
This patent makes no sense on many levels.
They indeed do not mention the size of their device.
My plan would be to use this in ultra dense protium excitation, which produces heat and muons ( see Holmlid's and Kotzias's works). So any sign that it does indeed produce electricity would be satisfactory. D µ D fusion complicates things too much atm due to safety and I need to get a rig going before I buy some deuterium, failure can also quickly get expensive. So, I will stay with protium for now.
That's 25.6 Zettahertz.
Convenience link for double checking the result: https://www2.chemistry.msu.edu…ch/virttxtjml/cnvcalc.htm
What then would be the "integer multiple of this frequency" ? I am sorry I have to ask I do not have lots of time.
So to recap I would need a signal generator, an HF amplifier and an oscilloscope. I had a look at the HF amplifiers on ebay, these definitely are not cheap hobby electronics devices.
I was planning to replicate Holmlid's experiment since I have the necessary equipment in my home lab. However, I gleaned from various sources, including Holmlid himself, that using the decay of the muons directly is better than converting heat to electricity. So I would rather start from here.
In my research I stumbled upon this patent : Electricity generation from muons.pdf
The basic idea is that you trap the atmospheric muons with an alternating magnetic field which you create by running an AC current through a copper coil at a frequency wich is " an integer multiple of the Compton wavelength of the muon". Then the trapped muons decay and the electrons are trapped by another coil that sits inside the first one and flow to a load.
They say the COP is 380, which is tremendous.
The idea seems simple enough. In practice ( and because I am a humble amateur chemist and I know little about electronics) I need to know :
1) if this is doable with a commercial signal generator such as this one ( signal generator ).
2) what frequency are we talking about exactly ? I found one website according to which the Compton wavelength of the muon is 11.734 441 11 x 10-15 m
If 1) is no then could someone tell me what to get to replicate this patent ? Thanks.