One billionaire is already doing that.
Malcolm Lear
Member
- Member since Oct 13th 2014
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Posts by Malcolm Lear
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Power source is irrelevant, just measure the voltage across a brown resistor and all is known. A white resistor no doubt is totally useless.
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I'm also sure it will happen, same old Rossi magic stage show.
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It looks like Rossi's fishing has resulted in a catch.
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Rodney Nicholson
Hi Andrea:
Are you planning to invite representatives from the major news media to the demonstration in October/November?
Thank you.
Rodney.
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Andrea Rossi
Rodney Nicholson:
This issue does not depend on me.
Warm Regards,
A.R. -
Patrick Ellul
Dear Andrea,
It seems like you’re again losing some degree of control over your product, when you say “This issue does not depend on me.”
Is this because of your new partner/s?
Best regards
Patrick -
Andrea Rossi
Patrick Ellul:
Yes.
Warm Regards,
A.R.
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I agree a perfect plasma is a good conductor, however we are talking here of the Quarkx which by all accounts creates a plasma from a arc passing through a gas. Such a plasma relies on sustained imperfect conductivity to produce the required heat to form the plasma, hence the observation of dynamic negative resistance.
Rossi however wants it both ways, the heat and light generated from a relatively high resistance of a sustained arc and the good conductivity of a near perfect plasma.
If Gullstrom ever reads this forum, I hope he ignores any pressure from Rossi and measures what really matters, i.e. the input voltage. -
xxxElexxx wrote,
'Yes plasma has extremely high conductivity'
I'd say the fact that a plasma is very good at producing light and heat radiation is an good indication in most circumstances its a rather poor conductor of electrical current.
Of course the QuarkX is an exception. Lets hope Gullstrom was allowed to measure the input voltage or maybe that wasn't possible due to a magic Rossi PSU producing proprietary waveforms.
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Silver
Dr Andrea Rossi,
Your measurement system described in the Gullstrom-Rossi paper is perfect. The circuit is very simple, the plasma is a conductor, as everybody knows, therefore placing a resistance with a known ohmage and measuring the voltage across it, the current is obtained by the Ohm equation, as well as the wattage.
Godspeed
SilverQuoteWell there we have it, 'the plasma is a conductor'. Just one more step to assume its near or is zero ohms and we have a scientific revolution.
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Alan/Dewey many thanks for the nod that something maybe forthcoming ))
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I'm just waiting now for Rossi to come up with the external pulse solution to his flow problem.
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There may be errors here and a few bits I can't discern, but it does seem to calculate out. I think Rossi made a typo and used 2988 rather than the correct 2898 in the black body calculation, but not a big problem. I'm no mathmatician, but I'm a little confused why the Boltzmann constant used is 5.67e-12 rather than 5.67e-8.
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Thanks for the info Alan, really nice. I love the parts list, really affordable practical research
If I have time whilst the students are away, I'll try something similar.
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Nice toy Alan, perhaps I should build one ))
What gas, voltage, pressure ???
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Yes, I agree. Guilty or not, that is unlikely.
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So you are saying a plasma across a 1.5cm gap is created at less than a volt?? If so, its pointless discussing further.