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Oystein Lande
July 23, 2017 at 1:18 PM
Dear mr Rossi,
Regarding the Rossi-Gullstrom paper:
The total power supply was not mentioned, but some say you used a 24 V battery?
If this is correct your total input power to the experiment setup would be 24V * 0,1 A = 2,4 Watts.
Can you confirm the battery voltage?
Regards
Lande -
Andrea Rossi
July 23, 2017 at 1:57 PM
Oystein Lande:
Our power source can be either 120 or 220 V AC, or we can use 24V DC batteries.
Obviously your calculation is wrong, because one thing is the voltage at the power source, a totally different thing is the voltage that goes to the E-Cat through the circuitry of the control system.
In the same Gullstroem-Rossi paper you can read the voltage measured by the 2 voltmeters.
Warm Regards,
A.R.
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Silver
August 15, 2017 at 6:12 AM
Dr Andrea Rossi,
Your measurement system described in the Gullstrom-Rossi paper is perfect. The circuit is very simple, the plasma is a conductor, as everybody knows, therefore placing a resistance with a known ohmage and measuring the voltage across it, the current is obtained by the Ohm equation, as well as the wattage.
Godspeed
Silver - Andrea Rossi
August 15, 2017 at 7:47 AM
Silver:
Correct.
Warm Regards,
A.R.
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Mario Marini
August 4, 2017 at 5:57 AM
Dr Andrea Rossi:
Looking at the paper Gullstrom Rossi I understand you measured the wattage across the 1 Ohm resistance to determine the wattage in the circuit, based on the rule of the circuit with two resistances of which one has a known value in Ohm, the other has not. I learned this at the school of electrotecnics: when a circuit is made by a power source and 2 reasistances, to know how much is the energy in the circuit you can measure the voltage across a resistance with well known ohms and get the amps from the ohm’s equation. Multiplying V x A you know the amount of energy in the circuit, less the dissipation caused by the resistance.
Am I correct?
Mario -
Andrea Rossi
August 4, 2017 at 2:20 PM
Mario Marini:
Exactly.
Warm Regards,
A.R.
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