stefan Intermediate

LINR (that is pretty funny in and of itself) - with one exception, we have found math errors, some unintentional self-deception, some see what you want to see
and / or orders of magnitude measurement issues in the projects we have parked. The remaining…

(Quote from Tony)

What, that's what's fun. Have you ever tried to solve a crossword, if you had all the details it would not have been so fun. I'll tell you that this bus load of people is training their brains and will probably have much less chance of…

(Quote from axil)

No, it's not related to QM, it's measured values the angular momentum of the electron is measured to hbar, then the precession means that what's left of the total angular momentums is hbar/2 that's happen to be the same as the intrinsic…

(Quote from axil)

skip that, that was an speculation. It should be that a each loop have two possible direction and they coop to point in the same direction, much like magnetic materials.
then by setting the resulting angular momentum to that of…

(Quote from axil)

explain
http://www.c-lambda.se/a-deep-question.html

Is it just a coincidence?

(Quote from Adrian Ashfield)

Is two wrongs equal a right?

Sometimes you find that you cannot employ good controls or use scientific principles like a double blind tests. For this case it's so easy that I think they have actually used a control but not…

(Quote from IH Fanboy)

DNI agrees with you on this, but maintain that this is an after construction. I maintain that it does not matter, let's give an ack on what is a good method and if not employed in a proper validation run we can bash it.

(Quote from DNI)

We cannot possible draw any conclusions from the information. What we can do is to make an ack that a suggested method ids ok in principle and the current stated method by Andrea is to measure over both resistors. Now how would you spoof…

(Quote from Nigel Appleton)

No, this is correct for the case when you measure the voltage over the brown resistor and not both of them. The paper could be interpreted this way so I understand your point. But if you measure the voltage over both IHFB is…

Well the paper is vague so supplementary information is needed and what Rossi now state is reasonable. To rehash IHFB post a little and focus on power.
The measured voltage are over both of the resistances e.g. you can do ...

P = U^2/(Rbrown + Rrector)…

Malcolm,

Rossi is right. Consider this handy-dandy diagram:





That is how I now understand it to be configured. So if you assign a resistance to R (REACTOR) other than zero, you are decreasing I. So by assuming that R (REACTOR) is zero, you are…

(Quote from Adrian Ashfield)


That would be a possible way to do it. But that is not how it seems to be done in the report. The power in is calculated from "Energy input: V=0.1 R=1 Ohm → W=0.01" where V is the voltage over the 1 ohm resistor. Hence…

(Quote from Adrian Ashfield)


BTW:
One of your post went into the clearance thread cause the moderators wanted to chill down the discussion me thinks.

(Quote from randombit0)

Sure, if the resistance of the reactor is less than 1ohm, you are correct, but that is not stated in the article which shows that one need hidden facts to interpret it correctly, which indicate that the report needs to be…

(Quote from stefan)


Ha, yes. Lugano repeated.

If the brown resistor is a resistor in series of the reactor you will have the same current U/R = 100mA going through both systems.
Now the power is I^2R which means that the power can be anything in the reactor depending of the resistance of it. So…

(Quote from Zeus46)

Zeus:

If they put a resistor inside the heat exchanger with a resistance that yielded the same output power and documented it I would be much more pleased than
with what we have now, does he mean that the 1 ohm resistance is a…

I just want to add,

No dummy, how did they validate their setup?

(Quote from axil)


I can do math quite well, and I work mainly in LENR to try to understand MIlls theory and explain his stuff. That's about how much I can contribute. I actually think that the story is quite humorous, here is a story line of my…

(Quote from maryyugo)

I mean your link, wasn't that mail referring to the bunch of swedes that hydrofusion took with them to Rossi and performed a test with their own equipment finding a COP of 1 and then rossi needed to explain away this and as a result…