stefan Member

To raise the mind from the microscopic to macroscopic,

RM predicted the acceleration of the expansion of the universe and his calculated value seam to be smack in the middle or a little high.
Recent calculations of the accelleration seam to prove that…

I can understand the frustration coming from people who have probably never done basic scientific research. The problem becomes especially intense when the research effort is applied to a phenomenon before it is understood. Generally, basic science…

RM is a perfect antipod to the man whose name we shall not say );
No obscure posting on the blogs instead overly detailed technical papers. In this case it describes silver aerosolization experiment. Looks like RM really enjoys what he is doing. I wish,…

(Quote from Alberto)

Is it surface temperature per watt of output power or surface temperature per input power. You will basically draw two very different conclusions depending on which is the case.

Well my experience is that if the result is against the view of the one doing the peer, the peer can stall the process and ask for more detail and in the end
although the result is proven still reject it because it is against their intuition. LENR is…

(Quote from RobertBryant)

For instance if the reactor/box configuration is idealized as concentric cylinders
the power output assuming the ambient is 80C is 352W
but when the reflected heat from the box is accounted for the
net power output is …

(Quote from THHuxleynew)

The method you are using is erroneous.

The accepted method is to calculate Q12 using A2,A1,E1,E2
Using this method I get a wall temperature of around 40-42C for 300W output from the reactor

Assume that the convective transfer is the same inside as on the outside.

then heat from box to outside air is

Q1 = K (T1 - T0) A

Heat to inside air is (air is 10 degrees hotter)

Q2 = K (T2 - 10 - T0) A

in balance the heat flowing through the…

(Quote from stefan)


So say that the heat is 276W/m^2, now convective cooling is around 10W/Km^3 this means that at around 30 degrees
we can match the radiating coolant with convective cooling and this is assuming no forced convection.

The air is…

(Quote from Walter Pegeto)

Yes it is indeed hard to swallow. But models are models and they can work in some part ans not in some other part. Typically QM is used for smashing particles and you have good matches. The problem
is that it is a tuned model…

(Quote from Walter Pegeto)


The Dirac equation can only be used to describe the kinetic aspects of mass. It obviously fails to describe dense mass. Otherwise teachers could show their students all the fantastic relations between proton radius/mass/moment…

(Quote from Walter Pegeto)

Randel Mills GUTCP takes another view on this. I find that work creative and thoughtful and might get to the finish line in the end.
And this has not stopped our Wyttenbach from spinning it to the point that he at least…

The anemometer info is here, by the way:

https://www.kk-custom.co.jp/emp/CW-60.html

You can Google translate it.

(Quote from Zeus46)


It is a hot wire type. But the same principle applies.

The HP data collection gadget does some averaging. I am not…

(Quote from Ascoli65)


Nope. It is measured with the anemometer. It does seem impossibly close, so I zoomed in some more to the individual data points. You see varying separation. Then I subtracted watts from air speed for each 5 s interval. That is, of…

(Quote from Ascoli65)


It's not fixed errors, looks like the errors is in the order of 0.025% for wind speeds, sounds small to me, but one has to verify this against the relative errors of the actual anemometer (precition and not systematic error)
which…

The measured energy out is the energy from the blower wall plus the energy from the air to the blower which both comes from the reactor so the effect this has on the system should be really really small e.g. leakage out of the system besides air flow. I…

Let's try a little calculation.

sigma = 5.67e-8 W / m^2/K^4

According to Stefan Boltzman. Att T = T0 + 300 degrees surplus at T0=300K

black body radiation wattage/m^2 from the inner surface:
j1 = sigma T^4 - sigma T0^4= 6889 W / m^2

No let's say…

https://revolution-green.com/m…nr-300-w-produces-2-3-kw/

In the comments, site owner Simon Derricut puts up one of the better Mizuno/LENR/PF's defenses I have read. Some good ideas also about this HM/JR paper. Lengthy at times, but worth a read.

(Quote from stefan)


If so, I will take back my comment about his mothers mustache.