For alumina, ir band e is high, total power e is low. So your argument fails because with e=1 you get the temperature roughlt right, but overestimate the output power at that temperature by a factor of 2 (in this case)
Clear as mud. Thank you.
That is discourteous. It is quite a complex issue, though very possible for you to understand, and for a long explanation you need to go over the previous thread reading the long replies from both me and paradigmnoia to randombit0. Or you could go over the original thread on here where I and others discussed the issue and why it exactly explained the cop acceleration, as well as the artificial cop=3.
It would I think not be fair to everyone else to go over things again on this thread, but if you are interested and make a new thread I can answer all challenges, as can Paradigmnoia if he has not lost the will to live over repetitions of this issue!