He also says these fill-up speeds worked. They kept the water level the same. In both the cold fusion cell and the control cell. The current and the fill-up rate was exactly the same in both. So the excess heat was not caused by them, and it was not hot enough to affect the water level with extra evaporation.
As I said, he confirmed the different temperature was not high enough to change the fill-up rate.
Jed: on this thread: 200 years old physics means that the evaporation rate can be calculated from the temperature.
In that case we have something not understood about this experiment. The temperature difference between the active and control cells is around 2C - 65C to 67C.
You (please do it - I did it many pages ago - but I'd appreciate a check) can calculate the two different equilibrium vapour pressures for H2O. The graph of equilibrium vapour pressure goes up sharply as you approach 100C - where it is 1 atmosphere (100kPa).
Vapour pressure of water - Wikipedia
65C 25kPa
70C 31kPa
Interpolate: difference between 65C and 67C is 2.4kPa. Or 2.4% of 1 atmosphere.
You can then work out the number of moles of H20/D2O difference in evaporation between the two cases. It will I am sure not surprise you that it is roughly 2.4% of the total amount electrolysed, and hence the total fill-up. (By the same reasoning the total evaporation is roughly 27% if the electrolysed amount).
I say roughly because partial pressures need to be converted to moles, but:
The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas. Because it is dependent solely on the number of particles and not the identity of the gas, the Ideal Gas Equation applies just as well to mixtures of gases as it does to pure gases.
So: a mole fraction of 2.4% corresponds to:
2.4% mol H20 vs 100% mol (H2 + 0.5O2)
Or a 1.5X increase by mass
2.4% X 1.5 of 162cc = 6g ~ 6cc (I remember it being lower when I calculated it before - but I'm sure you can correct this).
Anyway - even 1cc would I believe matter since Staker says the meniscus level is critical to the calorimetry.
I am very glad you are in communication with him - you will be able to resolve this.
If he kept the experiment under a very high pressure - e.g. 5 atmospheres - that would reduce evaporation and hence the magnitude of this effect? he says he uses a positive pressure but I imagined only a small positive pressure to prevent atmospheric ingress.
Had he published a few more details we would not need all this analysis...
I assume that we do not have the exhaust gasses cooling down outside the calorimetric boundary such that the condensed vapour can return to the cell because that would mean that varying evaporation, or D2 vs O2, would change the calibration constant. Perhaps though this is OK? The heat of vaporisation is much smaller then the excess heat - so that is not the issue. But differential heat transfer from outside to inside due to conduction through variable amounts of liquid is an issue. What do you think?
THH