Uh, normal star like
1/1H + 1/1H → 2/1D + e+ + νe + 0.42 MeV
where can extra 1Mev come? Is it energy from coulumb barrier and "cools" target?
eros
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Posts by eros
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We do not see any peak at 511keV in the GS5.2 spectrum. So, this reaction must not be happening at any significant rate. In fact, there can be no
significant amount of positrons for lack of the 511keV peak.Yep, it renders one claim in one theory lie. Or something quite strange happens inside Ni..? (Z+1, Ni->Cu ??)
There is posible H(p e-, ve)D, but it don't do braking radiation we have seen. And theory says that D produced in rest. So ve needs to generate extra
(1.4M+511k)=1.9Mev But ve already near c and it mass small. Can ve change it mass? Or where energy/mass can go? -
And where e+ go? where is 511kev?????
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But you must realize that the energy to launch the proton at >1MeV must come from somewhere and must be capable of acting on the single object.
The only source capable of acting with such energy on a single proton would seem to be a nucleus, and for the nucleus to give up >1MeV of energy,
it must give up some of its mass.Have you idea why H(p,e+ ve)D 1.4Mev positron hit Ni and do brake radiation instead collision with electron and not do ̃511kev gamma?
Where reaction go? On, in or away Ni?
Or other ideas?Is there evidence that Rossi do 500kev gamma? Is heater remove danger coupled that?
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There was not lithium. It does not recover from the oxide and hydride. Even if by some miracle is going to happen - instantaneously reacts with water
vapor. Hydrogen is not dry. Sodium chloride is bad dryer.It dos not need miracle, only temp an carbon:
http://www.globethesis.com/?t=2121360065450956Equilibrium is ofcourse moustly oxides, but some metallic Li appear.
It is not practical way to produce Li metal, but can do Li wapours.
H2O is not H2O with C it is CO + H2 at 1350C almost 100%. -
the kinetics of NiO reduction as a function of temperature. The most important point is that there exists a critical temperature, below which
reduction of NiO occurs slowly and is incomplete. Above this critical temperature (1173 K) reduction occurs in a matter of seconds and is complete.Ouh, you maybe right. It may be important. I have no idea is it important for LENR to keep lower than curie points or higher. Some test say success
in lower reduction temp. But is there tests done with higher temp reduction step? -
The reaction occurs at a lower temperature, but not always. And at 1200-1350 almost always starts. At least I was.You got Li vapour in 1350C in 1atm to coat some of your Ni particles.
This temp in 1atm is near max posible, because hotter boil Li away and then it stop.
Do Li deposition in vacuum then max H2 pressure, keep only redhot or slight lower to keep it going longtime. -
Freethinker's report: docs.google.com/document/d/13X…TKLPEhT8/edit?usp=sharingQuote
Ni powder was also baked in air for 2 hours at mild temperatures.Hello I think baking make some oxides that make fractures. Then H2 reduce baked Ni (200-400C etc ~1bar).
After reducing clean surface make Li vapour to coat all/everywhere (even dummy fuel (Btw Al is real fuel not dummy) in
some experiments) Ni particles.
Li vapor deposition is easier in vacuum.
Then add H2 pressure (̃10bar), keep where Li is molten. Theory says low temp is more efficient for fusion, but diffusin etc is
done faster in hotter.
It may need stimulus, try some lines found Rydberg formulas is my guess..
Some publication say ~500C ~1450nm may work.. -
eros wrote:
Quote: “ Lead (Pb) inside reactor is not good idea. It may go fission with deuterons.”
Could you justify that. Lead is not fissile or fissionable with or without deuterons, as far as I know. But if it did fission, so much the better.…
I have not done calculations yet, but I give educated guess that lead may support fission chain reaction in molten Li metal. Some free neutrons max 6.
Other heavy elements may do also, Bi210 maybe, U238 sure (8 free neutrons) -
Lead (Pb) inside reactor is not good idea. It may go fission with deuterons.
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Experiment found "mouse". When add enough cheese pressure (10bar or more) it feed more mouses. Then add mouse hole (Mg) and all mouses want to go
hole. Then play song of cat.. -
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The spectrum has every indication of being Bremsstrahlung ("braking") radiation
the Bremsstrahlung spectrum has a
sharp cutoff at the initial energy of the electron. The fact that this spectrum shows energy out to beyond 1MeV means that you must have MeV+
electron energies inside! This is a big deal. What LENR theories presently can account for MeV electrons? Actually, there appears to be energy out
to over 1.4 MeV in the Bremsstrahlung. MeV protons will not create this spectrum (too heavy and low speed).Theory author dosn't say all, but if 1.4Mev positron fits..:
--clips--
In the H(p, e+νe)D reaction via the H-H bond collapse, D atoms/ions are produced in rest
because their recoil energy in the positron and neutrino emission is below 0.1 eV
--
For the power released in the
H-H fusion, average values of about 60% carried out by neutrinos
--
average energy of about 0.84MeV carried out by neutrinos in the H(p, e
+νe)D reactions
--
As seen in the cases of Pd and Ni in Table II, the powers released in the D-D fusion
are bigger than those in the respective H-H fusion by a factor over one billion.
--
However as argued in Section.9, even in a Li permeated metal hydrides
with neither deuteride nor D2 gas, the D-D fusion takes place and generates
neutrons, protons, tritons and 3He ions of a few MeV energies. Neutrons are captured by
6Li after slowing down and produce tritons and α-particles.
--
In the reactor system charging ordinary hydrogen gas, contribution from the H-H
fusion is only 1.1% of the total power releasedTable I. Cross-section factors S(0) and
Q-values of hydrogen burning fusion
reactions [16, 17].
S(0) (MeV · b) Q (MeV)
H(p, e+νe)D 3.4 × 10−25 1.4
D(p, γ)3He 2.5 × 10−7 5.5
D(d, p)T 0.053 4.0
D(d, n)3He 0.050 3.3 -
more importantly, build a proper theory.Theory is already here. Even in there forum you find it, public from 2012.
--clip--
Suppose we may charge a test reactor with Ni/Mg2Ni grains, mixed LiH/MgH2 powder
and hydrogen gas. When we apply a pressure of 10 bars to the gas, its Gibbs energy
increases by 9kJ/mol=0.09eV/molecule at T=773K(kBT=0.067eV) [25] and results in
a gain of dissolution into the Ni/Mg2Ni grains by a factor of exp(0.09 / 0.067) =
3.8. This implies the gain of fusion rate and hereby power released by a factor of 15.
Through this treatment we may convert the Ni/Mg2Ni grains substantially into the
hydride NiH/Mg2NiH4 grains in which some 10 percent of hydrogen atoms occupy O-sites
in the hydride grain crystals forming 3-pairs as seen in Fig.1. This leads to the trebly
coherent collapse of H-H bonds with the enhancement of 1.6 × 1044 at 773K recalling
Eq.(28).
We begin a test experiment by pre-heating the reactor at room temperature. At first,
MgH2 molecules dissociate and form Mg2Ni or Mg2NiH4 molecules. The LiH molecules
dissociate through the physisorption and then chemisorption processes on the surface of
Ni/Mg2Ni grains more quick than hydrogen molecules due to their large dipole moment
p(LiH)= 2.0 × 10−29(C · m) comparable with p(LiF)= 2.1 × 10−29(C · m) and weak bond
strength D(Li-H)= 2.47(eV) compared to D(H-H)= 4.52(eV). The dissociated H atoms
are absorbed by the grains leaving Li+ ions and mobile s-electrons.
When the Li ions and mobile s-electrons moistens the hydride grains if nessecary under an activation by
corona discharge or electron or light irradiation, the coherent H-H fusion starts up with an
initial large enhancement and quickly heats up the hydride. This produces D-atoms in the
hydride together with lattice vacancies which are refilled by H-atoms under the presence of
the pressure H2 gas. The D-atoms diffuse with the diffusion coefficient of D0 ∼ 10−7 m2/s
at a high temperature towards the full clustering at O-sites [26, 27], hereby the trebly
coherent D-D fusion takes place resulting in the reaction energy released far larger than
the H-H fusion as seen in Section.11.
--/clip-- -
If you wear your tin foil hat, the signal is very clear.
Alumium may protect some and signal are lost..
Btw wikipedia write about that secret song:
..energy is at a specific resonance frequency which depends on the strength of the magnetic field and the magnetic properties of the isotope of
the atoms..I say try some voices which mouse likes..
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And mouse needs more stimulus than cat..
Have you seen number 80 in talk somewhere?
Rossi had this information 2012, maybe earlier.
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Quote from eros: “"Mouse" needs stimulus but give power away in neutrinos.”
Can you elaborate?--clip--
Here, the average energy of about 0.84MeV carried out by neutrinos in the H(p, e
+νe)D
--D2 gas of a fraction of about 1/6000. This
contaminant D2 gas results in an energy released by a factor (1.5 × 10−27)(6000)−2/5.2 ×
10−37 = 80 with respect to the H-H fusion power
--/clip-- -
No possibility of induction heating. Even with a powerful power supply problems. maximum power I have 350W-400W ..
The fact that the graphite is combusted in air at a temperature 400 gradusov know.400W should do lot if all go inside material. 2kw induction coocking plates are common too. Quite easy to modify. (I have one, but it have
3hrs timer to shutdown that make it useless. It have temp and power level logic ready, but 3hrs not do and too much work to reverse engineer.
More easy to do from scratch. Or wait delivery from china..)You can wrap graphite tube to protect it from oxidazing lot. Cement, glass etc. Cloced container may do also, it saturate CO level then stop.
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Oh I forgot don't rinse NiMH stuff well. It wash LiOH and KOH away. They are maybe needed for reaction.
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I make a new one, with a graphite tube.Graphite is good conductor for heat+el. resistor coil insulation maybe hard or maybe should use induction heat?
Graphite can do CO, which do low temp Ni carbonyl. Be carefull. Anyway amounts are small and you had
some Ni experinces before..CN.pdf paper says that reaction occur in molten Li enviroment. Other alkalis may do also. Your temp 1350C is enough with graphite (from NiMH) to
carbothermal reduction of Li and wapor deposition to Ni grains.
I think that is why you need so much temp. If use some drops Li metal needed temps may drop dramatically.
Or go high temp and do reduction in some hours (vacuum is best) then go hydride generating temp (~300C), load H2 and give EMP:s.
After reduction powder is maybe pyrophoric don't give oxygen or water or it may go unefficient.In mild temp your equipments may last long and service well.
Btw what you think to use 2000W halogen pipe for reactor tube? It allow 1100C continous surface
(inside can be lot hotter if use induction). Quite cheap 10-12mm quartz tube..?
SiO2 don't resist molten Li or carbon, but may last long enough for exeperiment if not flooded with Li..
https://www.radium.de/en/produ…based-rjh-ts-2000w230cr7s -
Therefore as beginner you have to catch up some parameters undeniable by LENR specialists here as using for example low pressure during
runs.It may work in low pressure. But claims say that 1->10bar do reaction 15x faster.
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It seems you aren't an engineer because sorry but you mix too much things about induction heating.Yeah maybe or maybe not. I don't classify me, others can do. Eh you think engineers are better than others ?
Mix things maybe, you mean that I need use leters MP only instead EMP, not as Mr Maxwell teach?
When write I drop letters that are posible to google/understand - not exact. There are IPR things also to think it is not wise to say
everything, only things that find easilly.
Btw papers say it should be EMP, but success replicators do moustly MP.Quote
About Rossi, yes his powder is "heated" by induction also this the reason why all part around of his device are builded by amagnetic matters
to concentrate magnetism up to powder.Make sense if there is room for RF or he use alternating fields. Or IPR things force to use harder way stimulus.
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By this fact, it isn't his target "to heat his powder" , by this way he has researched another behavior............stimulus. If he make power he need think how to cool it, not heat. Only smallest posible stimulus to get COP.
"Mouse" needs stimulus but give power away in neutrinos.Quote
Don't focus on complex heating system first rather a big reserve of power by 380V AC.induction heating is less broblematic as high temp resistors. Only some power fets more. And it can do maybe some stimulus if got things right..
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You talk about how to make "stimulus" , it's better to find how powder could have a better answer from theses "stimulus"..Wikipedia writes:
"energy is at a specific resonance frequency which depends on the strength of the magnetic field and the magnetic properties of the isotope
of the atoms"I don't know is this anybody claims, but is so clear that it need to be write net that it not found claims later..
