Electric Fusion Systems

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Thanks!

Producing electrical energy through nuclear fusion is wonderful.

But the goal of a nuclear fusion reaction should be nuclear fusion, that is, the synthesis of new chemical elements. Then the problems of obtaining electrical and thermal energy will be resolved by themselves as part of this process!

Quote from Alan Smith

electricfusionsystems.co

This is based on Lipinskis work that originally was based on WWII German work "stolen" by US military.

The 7-Li-P reaction can be triggered by 50..100eV that are needed to strip off/polarize the paired inner electrons. key for efficiency is the forming of a highly momentum polarized surface of aligned 7-Li(+).

Lipinskis failed to do it, as they ignored by modelling. Let's hope they really can get a sustainable COP > 3 process.

Is this a protonic or a neutronic reaction ? Or both ?

Quote from Wyttenbach

This is based on Lipinskis work that originally was based on WWII German work "stolen" by US military.

The 7-Li-P reaction can be triggered by 50..100eV that are needed to strip off/polarize the paired inner electrons. key for efficiency is the forming of a highly momentum polarized surface of aligned 7-Li(+).

Lipinskis failed to do it, as they ignored by modelling. Let's hope they really can get a sustainable COP > 3 process.

The reaction is 7Li+1H > 2He + ~17mev

Transmutation of chemical elements at a fundamental level occurs with any movement of matter (this is an absolute property of the movement of matter) along the channel:
ῡ_e + n → p + e^- + ῡ_e + 13,6 eV

Maybe however from the theory side to a replicable device, the path is long

Quote from Aleksandr Nikitin

Transmutation of chemical elements at a fundamental level occurs with any movement of matter (this is an absolute property of the movement of matter) along the channel:
ῡ_e + n → p + e^- + ῡ_e + 13,6 eV

Quote from Cydonia

Maybe however from the theory side to a replicable device, the path is long

And without a theory-compass, you can wander for a long time through the forest-experiments.

Who was the first between the chicken or the egg ? Great question..

Quote from Aleksandr Nikitin

And without a theory-compass, you can wander for a long time through the forest-experiments.

Quote from Cydonia

Is this a protonic or a neutronic reaction ? Or both ?

Obviously protonic! 7-Li has a neutron excess!

Quote from Cydonia

Maybe however from the theory side to a replicable device, the path is long

This were my thoughts here as well. It's nice to have a theory, it's maybe even nicer when your theory has COP>1 in a simulation. However, if either one has an error you can only tell when you have an experiment. And havening a device is then still quite a way to go.

Lithium-7 + 1H Reaction Overview

The reaction between Lithium-7 and a proton can be represented as:

7Li+1H→4He+4He(17.6 MeV)7Li+1H→4He+4He(17.6MeV)

In this reaction, a Lithium-7 nucleus and a proton fuse to produce two alpha particles (helium-4 nuclei), releasing a significant amount of energy, approximately 17.6 MeV. This reaction is aneutronic, meaning it does not directly produce neutrons, which is highly beneficial for fusion energy applications as it reduces the production of radioactive waste and avoids the neutron-induced material damage common in other fusion reactions.

Quote from k.e.kopp

Lithium-7 + 1H Reaction Overview

The reaction between Lithium-7 and a proton can be represented as:

7Li+1H→4He+4He(17.6 MeV)7Li+1H→4He+4He(17.6MeV)

In this reaction, a Lithium-7 nucleus and a proton fuse to produce two alpha particles (helium-4 nuclei), releasing a significant amount of energy, approximately 17.6 MeV. This reaction is aneutronic, meaning it does not directly produce neutrons, which is highly beneficial for fusion energy applications as it reduces the production of radioactive waste and avoids the neutron-induced material damage common in other fusion reactions.

Where are your neutrinos? Write with neutrinos. Without neutrinos there are no nuclear reactions!

i think someone went on the same way..

Our reactor works by taking a small amount of nickel, applying a catalyst, while in a pressurised hydrogen atmosphere. Truly novel reactions start to take place (beyond the usual chemical) and the result is a huge release of energy.

Our reactors uses nano dust suspended in a plasma matrix, excited by high voltage. We are experts in the principle of standing wave ratios, with resonant cavities, being used in tuning the plasma to the cavity like an antenna.

Quote from k.e.kopp

Lithium-7 + 1H Reaction Overview

The reaction between Lithium-7 and a proton can be represented as:

7Li+1H→4He+4He(17.6 MeV)7Li+1H→4He+4He(17.6MeV)

In this reaction, a Lithium-7 nucleus and a proton fuse to produce two alpha particles (helium-4 nuclei), releasing a significant amount of energy, approximately 17.6 MeV. This reaction is aneutronic, meaning it does not directly produce neutrons, which is highly beneficial for fusion energy applications as it reduces the production of radioactive waste and avoids the neutron-induced material damage common in other fusion reactions.

Quote from Cydonia

i think someone went on the same way..

Our reactor works by taking a small amount of nickel, applying a catalyst, while in a pressurised hydrogen atmosphere. Truly novel reactions start to take place (beyond the usual chemical) and the result is a huge release of energy.

Our reactors uses nano dust suspended in a plasma matrix, excited by high voltage. We are experts in the principle of standing wave ratios, with resonant cavities, being used in tuning the plasma to the cavity like an antenna.

Apply nickel Ni63.

The team i mentioned isn't mine... This is not my work..

However i'm pretty sure that at low energy it should exist 3 ways :

The protonic one, the spallation and the electron capture i like because no need of hydrogen especially.

Quote from Aleksandr Nikitin

Apply nickel Ni63.

No, neutrinos are not typically involved in the direct reaction of Lithium-7 (^7Li) with a proton (p) to form two helium-4 (^4He) nuclei, commonly written as:

7Li+→2 7Li+p→2α

(where α denotes an alpha particle, or a helium-4 nucleus), is a nuclear fusion process that does not directly involve neutrinos in its primary reaction pathway. The reaction proceeds as follows:

1. A Lithium-7 nucleus and a proton come together under conditions of high temperature and pressure (as in a fusion reactor or stellar environment).
2. If the kinetic energy of the colliding particles is high enough to overcome the Coulomb barrier (the electrostatic repulsion between the positively charged lithium nucleus and the proton), they can fuse.
3. The fusion process results in the formation of two alpha particles, along with the release of a significant amount of energy (approximately 17.6 MeV).

In this reaction, the energy is carried away by the kinetic energy of the alpha particles. Neutrinos are not produced in this specific fusion pathway, which is one of the reasons why this reaction is considered "aneutronic" – it doesn’t produce significant neutron or neutrino radiation. Aneutronic fusion reactions are particularly desirable for fusion power generation because they produce less radioactive waste and are safer compared to reactions that emit large numbers of neutrons.

Neutrinos are typically involved in other types of nuclear reactions, such as beta decay processes, where a neutron is converted into a proton (or vice versa) within an atomic nucleus, with the emission of a beta particle (electron or positron) and an antineutrino or neutrino. Such reactions are common in certain types of radioactive decay and in the nuclear fusion processes occurring in stars, but they are not a feature of the ^7Li + p reaction.

EFS's fusion process operates at significantly lower temperatures compared to traditional "hot fusion" methods, but it doesn't take place in a solid medium like many Low Energy Nuclear Reactions (LENR) are thought to. Specifically, EFS's Light Element Electric Fusion (LEEF) technology works at temperatures in the hundreds of Kelvin range, which is much cooler than the several million Kelvin temperatures commonly associated with other plasma-based fusion approaches.

Quote from k.e.kopp

Нет, нейтрино обычно не переходит в прямом состоянии лития-7 (^7Li) с протоном (p) с образом

Quote from k.e.kopp

No, neutrinos are not typically involved in the direct reaction of Lithium-7 (^7Li) with a proton (p) to form two helium-4 (^4He) nuclei, commonly written as:

7Li+→2 7Li+p→2α

(where α denotes an alpha particle, or a helium-4 nucleus), is a nuclear fusion process that does not directly involve neutrinos in its primary reaction pathway. The reaction proceeds as follows:

1. A Lithium-7 nucleus and a proton come together under conditions of high temperature and pressure (as in a fusion reactor or stellar environment).
2. If the kinetic energy of the colliding particles is high enough to overcome the Coulomb barrier (the electrostatic repulsion between the positively charged lithium nucleus and the proton), they can fuse.
3. The fusion process results in the formation of two alpha particles, along with the release of a significant amount of energy (approximately 17.6 MeV).

In this reaction, the energy is carried away by the kinetic energy of the alpha particles. Neutrinos are not produced in this specific fusion pathway, which is one of the reasons why this reaction is considered "aneutronic" – it doesn’t produce significant neutron or neutrino radiation. Aneutronic fusion reactions are particularly desirable for fusion power generation because they produce less radioactive waste and are safer compared to reactions that emit large numbers of neutrons.

Neutrinos are typically involved in other types of nuclear reactions, such as beta decay processes, where a neutron is converted into a proton (or vice versa) within an atomic nucleus, with the emission of a beta particle (electron or positron) and an antineutrino or neutrino. Such reactions are common in certain types of radioactive decay and in the nuclear fusion processes occurring in stars, but they are not a feature of the ^7Li + p reaction.

You, like everyone else, make the following fundamental mistakes:

to point

1) Temperature and pressure are derivative consequences of a thermonuclear reaction, and not conditions. It is stupid to copy the mechanical conditions on the Sun - this is a dead end.

2) There is no Coulomb barrier in the atom. An atom is like this from “birth”. The Coulomb barrier exists only in our heads. It is stupid to think that there are any barriers in Nature. Our World is non-mechanical.