Sounds like what I imagine the sun is, A rich in lenr fuels core using none flammable gas cushion micro tunnels ect.

Quote from axil

What Matsumoto has not done in support of his theory is to analyze the marks produced on matter for transmutation or whatever characteristics these marks indicate.

Matsumoto published “Radioactive Analysis of Palladium Used for an Explosive Cold Fusion Experiment” He compare the part of the Pd rod below the water surface compared to part above the water. This analysis indicated a reduction in the relative isotopic abundance of Pd-111 from about 15% to about 11% in the part of the rod below the water surface. Further, the part of the rod below the water surface when neutron activated showed Ru105 and In116 that was not present in the part from above the water surface.

Matsumoto published “Experiments of Underwater Spark Discharges with Pinched Electrodes. “Discharge products deposited on the electrode surface were examined by SEM-EDX, EPMA and XS. “Several elements were found by EPMA among the deposited material on the anode of palladium wire: nickel, calcium, titanium, sodium, aluminum, chloride, cadmium and iodine. They were not observed in a reference region of the palladium wire. Furthermore, nickel was clearly detected by XS. These elements could not be assigned to impurities but rather suggested to be transmuted during the electrical discharges associated with micro sparks. For example, chlorine, calcium and nickel could be transmuted by the capture of electrons, a proton and hydroxide with a potassium nucleus, respectively. On the other hand, cadmium and iodine could be transmuted by the capture of a proton and oxygen with a palladium nucleus, respectively. Such capture could occur in the highly compressed state of the hydrogen-cluster."

The highly compressed state is the electronuclear gravity for which I derived an equation elsewhere in this forum.

With iron wires, “Many ring products could be observed with SEM around the zone on the surface of the cathode that touched the water level. …After a few days, the ring products all disappeared, and in place of them, only the hexagonal products remained. This suggests that the ring products decayed to the hexagonal plates.

The ring and hexagonal products were examined with EPMA. … Besides iron from the host metal and potassium from the electrolyte, some elements of calcium, sodium, chlorine and cadmium were both observed in the ring and the hexagonal products. Two circular zones, especially could be seen for cadmium that were clearly separated from each other in the ring products…

Just to clarify, the EVOs or microsparks create EGOs which make the ring products which over a period of days convert to the hexagonal products.

Quote from axil

What Matsumoto has not done in support of his theory is to analyze the marks produced on matter for transmutation or whatever characteristics these marks indicate. How are those marks produced?

One apparent inconsistency is that Hackings radiation is thermal and follows a black body progression as the black hole evolves.

Is Matsumoto theory consistent with established micro black hole theory? The gravitational pull of such a mini black hole would be about 1 gee at a distance of 1 metre. Is this attractive gravitational force observed in the presence of the EGO?

The ring marks are produced by cold fusion reactions since they have never been observed in any other kind of experiment or any controls.

Hawkings proposed radiation whose origin is best thought of as entangled with the delocalization of mass within the black hole and its re-localization at some distance from the event horizon. (teleportation). Non permitted wavelengths within the event horizon reappear by interference effects at some distance from the event horizon. The idea that the radiation is light or is temperature dependence is based on a faulty assumption of a thermodynamic blackbody.

I use the term extreme gravitational object because these are quantum objects. Quantum objects do not have singularities. Electronuclear gravity is not universal gravity. If you had looked at the math elsewhere in this forum you would have seen the derivation of the electronuclear gravitation constant. Its value is 2.780204000E+32. The universal gravitational constant is 6.67E-11. That is 42 order of magnitude difference.

Electronuclear gravity does not apply to normal electrons or atoms. So, an EGO that radiates Hawking radiation doesn’t consume all matter around it, but they can and do consume some matter as you have indicated in your references.

Electronuclear gravity applies when an R-electron is involved. The R part signifies Riemann geometry which is time space curvature. The R-electron is present when hydrogen has phat radiation. Phat states are defined such that when they decay, they produce radiation with energies defined as follows: E=n²(ionization energy of hydrogen). Normal electrons don’t form EVOs, but R-electron will. Hydrogen does not self-compress, but R-hydrogen will.

R-electrons interact with the nucleus of atoms causing a degenerate state of the nucleus. Normal neutrons don’t turn into EGOs, they just decay to a proton and an electron. The “neutrons” from the decay of itonic nuclei shed the itonic net and collapse to EGOs.

When I am ready, I will publish all the facts and all the proofs. The first video in this series is called A Hack for Quantum Gravity.

Quote from axil

Why and how do EVOs create electronuclear gravity? How does this creation effect the EVO? These theories and models must be consistent with existing science. Provide links and references to that science.

All that has been posted on this site multiple times. I am not going to feed your rant.

Quote from axil

The wavelength of the radiation coming from a black hole is defined by the size of the black hole. Micro black holes will produce high energy radiation and a lot of it.

No. Because no light escapes from a blackhole. A blackhole is not a blackbody.The radiation is produced a long distance from the event horizon. Most importantly EGOs are produced by quantum effects so electronuclear gravity is not universal gravity.

If you want to know what radiation comes from an EGO then look at Reproducible, Anomalous Emissions from Palladium Deuteride/Hydride: Fusion Technology: Vol 30, No 2 (tandfonline.com) Clearly the radiation is not of any known kind.

To be clear, EVOs produce EGOs and the radiation EGOs emit (hawking radiation) will run an LEC.

Here is an image of a metal electrode to which numerous EGO have been absorbed.

Quote from Drgenek

No. Because no light escapes from a blackhole. A blackhole is not a blackbody.The radiation is produced a long distance from the event horizon. Most importantly EGOs are produced by quantum effects so electronuclear gravity is not universal gravity.

If you want to know what radiation comes from an EGO then look at Reproducible, Anomalous Emissions from Palladium Deuteride/Hydride: Fusion Technology: Vol 30, No 2 (tandfonline.com) Clearly the radiation is not of any known kind.

To be clear, EVOs produce EGOs and the radiation EGOs emit (hawking radiation) will run an LEC.

Here is an image of a metal electrode to which numerous EGO have been absorbed.

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I as I currently understand it, black holes are blackbody objects, but cannot radiate energy since they are the coldest object ‘surfaces’ in the universe and therefore they are pure absorbers. Each instance more energy is absorbed by a black hole, the black hole increases its surface area, thereby maintaining the coldest ‘surface’ in existence.

Quote from Drgenek

If you want to know what radiation comes from an EGO then look at Reproducible, Anomalous Emissions from Palladium Deuteride/Hydride: Fusion Technology: Vol 30, No 2 (tandfonline.com) Clearly the radiation is not of any known kind.

Here's a more accessible version...

https://www.lenr-canr.org/acrobat/RoutRKreproducib.pdf

Quote from Paradigmnoia

I as I currently understand it, black holes are blackbody objects, but cannot radiate energy since they are the coldest object ‘surfaces’ in the universe and therefore they are pure absorbers. Each instance more energy is absorbed by a black hole, the black hole increases its surface area, thereby maintaining the coldest ‘surface’ in existence.

A black body is defined as a perfect emitter. A blackhole has gravity so intense it can't emit light. So, a blackhole as a blackbody is a perfect emitter that can't emit light. That would be an antiblack body. Since the blackhole is perfect absorber, then its surface is the coldest possible "black body". Obviously, blackbody applied to a blackhole is a very perverted application of the term blackbody.

In a EGO trace in a film emulsion, a dark area is the Hawking radiation causing a reaction with the emulsion. An extraordinary white area, it the opposite. So, it could be an area where the interference pattern though space creates forbidden zones for Hawking radiation. It seems in the following image that white part implies forbidden reaction with the film emulsion. Maybe that why it is whiter than the background in the image.

Quote from axil

If the experimenters would have used a cloud chamber to observe the radiation that palladium hydride produced, they would have seen what Sveinn was seeing in his cloud chamber

I believe that a member of Frank Gordon's LEC group has done that, this might well be discussed at ICCF-24. I am not however able to say what was observed.

Quote from axil

As an overall criticism of the EGO theory, gravity is not an appropriate force to describe what is going on in LENR. IMHO, the appropriate force is the electroweak force.

Strange radiation is Hawking radiation from EGOs. The EGO mostly do not make light. In my patent application the energy balance indicated that the mass loss would have produced a bomb 1/10 the size of the one that was dropped on Hiroshima if the output had been light, but the measured excess heat was about 2871 BTU. That is because the major product instead of light is radiation that has mass. This mass can't be assigned to the standard molecular weight any of the reaction products. Rather, if one takes the gas produced from electrolysis, does the elemental analysis to calculate a fuel value. Then one compares the actual torque/energy via an engine test (the calculated torque/energy value is relative to equal power per gram of gasoline). Then one finds the calculated fuel value of the nuclear reaction produced gas is 13.3 KJ of energy per gram basis chemical composition. Whereas the torque/power yield is 40.08KJ of energy per gram of nuclear reaction produced gas. The nuclear reaction was proven by doing mass balance and stoichiometry. One measures and identifies the input and output gases to show transmutation.

Proton + R-electron = neutron. R-electron is a string of an electron and a Majorana neutrinos complex. R-electron + positron = iton. Electronuclear gravity is rooted in the electroweak force. The transmutation equations are based on conservation of baryons.

Quote from Drgenek

A blackhole has gravity so intense it can't emit light. So, a blackhole as a blackbody is a perfect emitter that can't emit light.

This is standard model physics propaganda. Some black holes are very bright at all energies. But worst they emit a large junk of their energy in the axial jet of the torus. So stay away from standard model nonsense. Black holes are far more complex that crappy Schwarzschild did predict. They more or less have a nuclear structure. Such structure are given/described by nuclear physics not by GR....